BIOLOGY LESSON NOTE ON HUMAN KIDNEY

Topic: Chemical Equilibrium – Equilibrium Constant, Calculations
Class: SS1
By the end of the lesson, students should be able to:
Chemical equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction in a reversible system, and the concentrations of the reactants and products remain constant (not necessarily equal).
It is dynamic, not static — reactions continue in both directions.
Example of reversible reaction:
\text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g)
For a general reaction:
aA + bB \rightleftharpoons cC + dD
The equilibrium constant (Kc) is given by:
K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}
Where:
Kc is a constant at a fixed temperature.
Example:
For the reaction:
\text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g)
At equilibrium:
[\text{H}_2] = 0.2 \, mol/dm^3,\quad [\text{I}_2] = 0.2 \, mol/dm^3,\quad [\text{HI}] = 0.6 \, mol/dm^3
Calculate Kc.
Solution:
K_c = \frac{[\text{HI}]^2}{[\text{H}_2][\text{I}_2]} = \frac{(0.6)^2}{(0.2)(0.2)} = \frac{0.36}{0.04} = 9.0
So, Kc = 9.0
\text{CO}(g) + \text{H}_2O(g) \rightleftharpoons \text{CO}_2(g) + \text{H}_2(g)
\text{N}_2 + 3\text{H}_2 \rightleftharpoons 2\text{NH}_3
2\text{SO}_2 + \text{O}_2 \rightleftharpoons 2\text{SO}_3
Chemical equilibrium describes a state where a reversible reaction proceeds at equal rates in both directions. The equilibrium constant, Kc, provides valuable insight into which side of a reaction is favored and is crucial in chemical analysis and industrial processes.
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